Figure 2

Steady state lactate concentration C in mmol/L as a function of the fraction of the maximum aerobic power Q _max when running with poles at the angle of inclination of 0.105 for 5-min steady state work rates.$v_1=2.08\text{m}/\text{s},{\overline{Q}}_{\mathit{vir}}=0.59Q_{\mathit{max}}$, $v_2=2.33\text{m}/\text{s},{\overline{Q}}_{\mathit{vir}}=0.66Q_{\mathit{max}}$, $v_3=2.64\text{m}/\text{s},{\overline{Q}}_{\mathit{vir}}=0.74Q_{\mathit{max}}$, $v_4=2.83\text{m}/\text{s},{\overline{Q}}_{\mathit{vir}}=0.80Q_{\mathit{max}}$, $v_5=3.08\text{m}/\text{s},{\overline{Q}}_{\mathit{vir}}=0.87Q_{\mathit{max}}$, $C=C_s=\frac{1}{2}Ln\left(\frac{1+\frac{p_0\chi }{d_0{Q}_{\mathit{max}}\left(1-Q_a/Q_{\mathit{max}}\right)}}{1-\frac{p_0\chi }{d_0{Q}_{\mathit{max}}\left(1-Q_a/Q_{\mathit{max}}\right)}}\right)/\chi$, $\chi =2.54m^3/\mathit{kg},p_0={10}^{-5}kg/\left(m^{3}s\right)/\left(J/s\right),d_0=1.1{10}^{-7}/{\left(J/s\right)}^2/s,Q_{\mathit{max}}=1886J/s,Q_{\mathit{LT}}/Q_{\mathit{max}}=0.88$.